MATHEMATICS PRIMARY 6 SECOND TERM
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MATHEMATICS PRIMARY 6 SECOND TERM LESSON NOTE
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
TABLE OF CONTENT
Class:- Basic 6
Subject:- Mathematics
Week:- 2
Topic: Money ( Rates, Taxes, Shares and dividends)
Behavioral objective:- At the end of the lesson the pu.pils should be able to:-1. Solve problems on taxes and Rates on population and economic Consequences.
2. Solve problem on buying and Selling of shares and dividends.
Instructional material/Reference material:- Learn Africa Mathematics UBE edition for primary school book 6
Building Background /connection to prior knowledge : Students are familiar with the uses of money
Content
MONEY
Rate – means what the government Provides for her people.
Example:- Agege Local government charges N5.50 monthly for the user: Find The total rent collected monthly From
(A). 50 stalls (B) 160 stalls
Solution:-
(A). Monthly rate collected for N50
Stalls is 𝑁5.50×50 𝑁275.00
Taxes: This is the money that Government uses to build schools, Hospitals, roads etc
Example:- Tax deducted from the taxable Income of an employee is 35K on Every N1. Find the tax paid if the Taxable income is N4,500
Solution:-
= (4,500×35)K = 1,575.00K = 1,575.00
Shares: The amount needed is Divided into units and each unit is
Called a share.
Example:- A metal manufacturing company Sells some of its 40K share to the Public who are ready to buy in Multiples of 200.
(i). What is the cost of 800 shares?
(ii). How many shares can I buy With N1, 250?
Solution
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
Cost of one share = 40K
Cost of 800 Share = 40×800 = N( 40×800)= N32,000
(ii). 40K can buy only one share: N1,250 will buy 1250×200 40 1 = 1250×5
= N6,250 shares
Dividends:- This is the amount Made from the goods sold at the End of the year. The profit is called Dividend.
Example: A share holder has 200 shares in a Company. How much is his Dividend if dividend are given at 5 1/2K per share.
Solution
Dividend on 1 share = 5 1/2
Dividend on 200 shares = 11/ 2 × 200/ 10 = N1100
Evaluation:-
1. An executive lady earns two million naira per annum.
(a) Work out her income tax b) Work out her monthly tax
2. At the Marina Car Park, Ώ400 naira is charged to park a jeep and Ώ250 to park a car. How much will the Car Park Authority collect for parking 250 cars and 360 jeeps in a day?
3. The IKEDC charge for a company is Ώ48275 VAT inclusive. If 10% was charged as VAT, how much was that?
4. Find the rent collected by Local Government Authority from 276 stalls at the rate of Ώ5600 per stall.
Class:- Basic 6
Subject:- Mathematics
Week:- 3
Topic: Length
Behavioral objective:- At the end of the lesson the pupils should be able to:-1. Recognise and convert the units of length
2. Apply pythagoras’ rule to find the unknown length of a given right-angled triangle
3. Identify pythagorean triples
4. Find the heights and distances of objects
Instructional material/Reference material:- Learn Africa Mathematics UBE edition for primary school book 6
Building Background /connection to prior knowledge : Students are familiar with the various ways of measuring length.
Content:-
LENGTH
The standard unit of length are:
– millimetres (mm) – metres (m)
– centimetres (cm) – kilometres (km)
10 millimetres (mm) = 1 centimetre (cm) 1000 millimetres = 1 metre
100 centimetres = 1 metre (m) 1000 metres = 1 kilometre (km)
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
Examples
1. 10mm = 1cm ∴ 18cm = 18 × 10mm = 180mm ∴
2. 1000m = 1km 1.08km = 1.08 × 1000m = 1080m
Triangles ABC, LMN and XYZ are right-angled triangles.
Bˆ, Mˆ and Yˆ are right angles (i.e. 90º) The side facing (opposite) each right angle is the longest side. This side is called the hypotenuse. That is, AC, LN and XZ are the hypotenuses of triangles ABC, LMN and XYZ respectively.
ABC is a right-angled triangle with Bˆ = 90º
AB = 3cm, BC = 4cm and AC = 5cm
Area of red square = 3cm × 3cm = 9cm2
Area of blue square = 4cm × 4cm = 16cm2
Area of red square + Area of blue square 9cm2 + 16cm2 = 25cm2
Area of black square = 5cm × 5cm = 25cm2
From the calculation, you will see that the area of the black square equals the sum of the areas of both the red square and blue square.
This is called the Pythagoras theorem. In this right-angled triangle ABC, pythagoras’ theorem tells you that area Y (black) = area R (red) + area B (blue)
Pythagoras’ theorem
In any right-angled triangle, the area of the square on the hypotenuse side is equal to the sum of the areas of the squares on the other two sides
Application of Pythagoras’ theorem to calculate the missing side of a right-angled triangle
Pythagoras’ theorem is usually written using the lengths of the sides of the triangle.
In this right-angled triangle ABC,
Pythagoras’ theorem tells you that
b2 = a2 + c2
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
The square of the hypotenuse side is
equal to the sum of the squares of the other two sides.
This rule is used to find an unknown side of a right-angled triangle when the other two sides are given.
Example
1. Study how the length of the side marked y is found.
Hypotenuse = 13cm
∴ 132 = y2 + 52
∴ 169 = y2 + 25
169 – 25 = y2
√144 = y2
∴ y2 = 144
y = 144 = 12cm
2. Find the length of the hypotenuse of a right-angled triangle if the lengths of the other two sides are 12cm and 16cm respectively.
3. A right-angled triangle has its hypotenuse as 10cm and one other side as 8cm. Calculate the length of the third side
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
Class:- Basic 6
Subject:- Mathematics
Week:- 4
Topic: Perimeter (Regular & Irregular Shapes)
Behavioral objective:- At the end of the lesson the pupils should be able to:-
1. Review work done on perimeters of plane shapes
2. identify rectangles that have same area but different perimeters
3. find the perimeters of compound shapes
Instructional material/Reference material:- Learn Africa Mathematics UBE edition for primary school book 6
Building Background /connection to prior knowledge : Students are familiar with the measurement of length and height from the previous lesson
Content
Perimeter
Perimeter means the sum of lengths of all the sides of a plane shape. It also means the distance round a shape, field or plot.
Formulae
Perimeter of irregular shapes/compound shapes
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
Evaluation:-
1. The perimeter of a rectangle is 78cm. Find the length if the breadth is 15cm.
2. A rectangle and square have the same areas but different perimeters. If the side of the square is 8cm and the breadth of the rectangle is 2cm, find:
( a) the length of the rectangle. (b) the perimeters of the square and the rectangle.
Class:- Basic 6
Subject:- Mathematics
Week:- 5
Topic: Area (Trapezium)
Behavioral objective:- At the end of the lesson the pupils should be able to:-
1. Define and draw a trapezium
2. Measure the area of a trapezium
Instructional material/Reference material:- Learn Africa Mathematics UBE edition for primary school book 6
Building Background /connection to prior knowledge : Students are familiar with the ways of measurement
Content
Trapezium
A trapezium is a rectangular shape joined with either a triangle at one end or a triangle each at two ends.
ABCD is a rectangle. BCE is a triangle.
∴ ABCD + BCF = ABED.
ABED is known as a trapezium,
that is a rectangle plus a triangle as shown in Fig 1
ABC is a triangle. EDF is also a triangle. BEDC is a rectangle.
Thus ABC + BEDC + EDF = trapezium ABEF
MATHEMATICS SECOND TERM E LESSON NOTE FOR BASIC SIX
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